a cottage industry produces a certain number of pottery articles in a day it was observed on a particular days at the cost of production of each article was 3 m

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Given :-

The total cost of production= Rs.90

Let the number of pottery articles produced be x

Therefore , cost of production of each article = Rs (2x + 3)

the total cost of production = no. of pottery articles produced × cost of production

According To The Question ,

90 = x(2x + 3) = 0

⇒ 2x²+ 3x – 90 = 0

⇒ 2x² + 15x -12x – 90 = 0

⇒ x(2x + 15) -6(2x + 15) = 0

⇒ (2x + 15)(x – 6) = 0

Now 2x + 15 = 0

⇒2x = - 15

⇒x = -15/2

⇒x – 6 = 0

⇒x = 6

⇒ x = -15/2 or x = 6

As the number of articles produced can only be a positive integer, therefore, x can only be 6

Hence , number of articles produced = 6

Cost of each article = 2 × 6 + 3 = Rs 15

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