An electric dipole of length 2 cm is placed with its axis making an angle of 30° to a uniform electric field 105 N/C. If it experiences a torque of 10/3 Nm, the
Physics
abhayabh
Question
An electric dipole of length 2 cm is placed with its
axis making an angle of 30° to a uniform electric
field 105 N/C. If it experiences a torque of
10/3 Nm, then potential energy of the dipole
1 Answer
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1. User Answers tanvi8053
Torque= PESin theta
10/3 = P × 105 × Sin30°
10/3 = P × 105 × 1/2
3.33 = P × 52.5
P = 3.33/ 52.5
P = 0.06 Cm
U= - pE Cos theta
U = - 0.06 × 105 × root3/2
U = -5.4J